Relationship Between Area And Perimeter

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This Lesson (Relationship betwixt surface area and perimeter of a rectangle) was created by past Timnewman(319) : View Source, Show
Near Timnewman: Tim is from the department of mathematics Kogi Country college of education Ankpa. Kogi Country,Nigeria. Feel free to electronic mail me at timtimazubuike@gmail.com for the solution of your mathematics problem or explanation of any concept in maths.it is absolutel

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Relationship between area and perimeter of a rectangle

This lesson is a continuation of the lesson
BASIC FORMULAE FOR FINDING AREA OF A RECTANGLE  and information technology will help you to solve harder problems that relates to area and perimeter of a rectangle.

We shall consider ii example here to enable you perform better when such problem is given to you.

In the previous lesson, we found that area and perimeter of a triangle is given by;,

A=LW
P=ii(Fifty+due west)

where Fifty=length,W=width,P=perimeter and A=expanse,

see the case beneath

Example 1

The length of a rectangle is two more than Than the width,if the surface area of the rectangle is 15cm^ii,find the perimeter of the rectangle.

SOLUTION

Allow width be w,
length =w+2
since Lw=15cm
Therefore,
(w+2)due west=15

w^2+2w=xv
w^2+2w-15=0

factorize the quadratic equation,nosotros have;

(w+5)(w-three)=0
This means that

w+5=0 or due west-three=0
so
westward=-5cm or west=3cm

But west=-5 is not the solution since width cannot exist negative.

Therefore,width is 3cm.

Call back that length=w+two
only due west=3cm
Hence,
L=3+2
L=5cm.

The length and width of the rectangle is 5cm and 3cm respectively.

Hence,
perimeter (P)=2(50+West)
simply Fifty=5cm,w=3cm
Perimeter (P)=2(5cm+3cm)
=two(8cm)
=16cm.

The perimeter of the rectangle is 16cm.

Example 2

The perimeter of a rectangle is 16cm if the its length is 5cm,discover the area of the rectangle.

Solution

Before wee find the area of the rectangle,,nosotros must commencement detect the width of the rectangle.

From our question,

perimeter P=two(l+west)=16
length =5cm,
And then,
2(5+w)=16
10+2w=16
2w=16-10
2w=6
w=3

Now,length=5cm,westward=3cm

Therefore Surface area A=Lw
A=5(3)
A=15cm^2

In determination , it is appropriate to make sure that when dealing with expanse and perimeter of a rectangle , y'all must obtain the parameters that volition help you lot to discover the area or the perimeter you are looking for.
Annotation:These parameters involves length and width of the rectangle.

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Relationship Between Area And Perimeter,

Source: https://www.algebra.com/algebra/homework/Rectangles/change-this-name532.lesson

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